5x^2-20x-8800=0

Solution for 5x^2-20x-8800=0 equation:

5x^2-20x-8800=0

a = 5; b = -20; c = -8800;
Δ = b2-4ac
Δ = -202-4·5·(-8800)
Δ = 176400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{176400}=420$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-420}{2*5}=\frac{-400}{10}
=-40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+420}{2*5}=\frac{440}{10}
=44
$